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2y^2-8y+16=154
We move all terms to the left:
2y^2-8y+16-(154)=0
We add all the numbers together, and all the variables
2y^2-8y-138=0
a = 2; b = -8; c = -138;
Δ = b2-4ac
Δ = -82-4·2·(-138)
Δ = 1168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1168}=\sqrt{16*73}=\sqrt{16}*\sqrt{73}=4\sqrt{73}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{73}}{2*2}=\frac{8-4\sqrt{73}}{4} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{73}}{2*2}=\frac{8+4\sqrt{73}}{4} $
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